2sinx+sin2x=cosx+1 2sinx+2sinx *cosx =cosx+1 2sinx * (1 + cosx) = 1 + cosx 2sinx * (1 + cosx) - (1 + cosx) = 0 (1 + cosx) * (2sinx - 1) = 0 1 + cosx = 0 cosx = -1 x1 = π (все остальные вне заданного интервала) 2sinx - 1 = 0 sinx = 1/2 x2 = π/6 x3 = 5π/6 Ответ: x1 = π; x2 = π/6; x3 = 5π/6
