C4H10+7O2=2CO2+5H2O v(C4H10)=2.24/22.4=0.1 v(C4H10)=2v(CO2)= 0.2 V(CO2)=0.2*22.4=4.48 V(практическая)= V(t)*80%/100= 4.48*80/100=3.584