√x*(√y+1) dy/dx = y √x*(√y+1) dy = y dx (√y+1)dy/y = dx/√x найдем интеграл обеих сторон integral (√y+1)dy/y = integral dx/√x integral ((y^½)/y+1/y) dy = integral x^(-½) dx integral (y^(-½)+1/y) dy = integral x^(-½) dx (y^½)/½ + lny = (x^½)/½ +C 2y^½ + lny = 2x^½ +C 2y^½ - 2x^½ + lny = C
