1) 9х -11>5(2х-3) 9x-11>10x-15 9x-10x>-15+11 -1x>-4 *(-1) x<4 (-бесконечност;4) 2) х^2 + 7х -8 ≥ 0 D = b2 - 4ac D = 49 + 32 = 81 = 9^2 x1,2 = -b ± √D/2a x1 = -7 + 9/2 = 2/2 = 1 x2 = -7 - 9/2 = - 16/2 = -8 Ответ: x1 = 1; x2 = -8(не удол) 1^2+7+1-8>=0 8-7>=0 1>=0 [1;бесконечност+)