log(9)x=log(3)x/log(3)9=log(3)x/2 9log^2(3)x-10log(3)x+1=0 log(3)x=t 9t^2-10t+1=0 t=(5+-sqrt(25-9))/3=(5+-4)/3 t1=3 t2=1/3 log(3)x=3 x=3^3=27 log(3)x=1/3 x=-1 2. log(6)6+log(6)(x+6)=log(6)(6x+36) x^2+10x+24<=6x+36 x^2+4x-12<=0 [-6;2] x>-6 + x^2+10x+24>0 x>-4 x<-6 ответ ]-4;2] log^2(0,5)x-log(0,5)x^2>3 t^2-2t-3>0 t<-1 t>3 log(0,5)x>3 x<1/8 log(0,5)<-1 x>2 x>0 ]0;1/8[ U]2;~[