sin3x=√2/2 3x= (-1)^n arcsin √2/2 + πn 3x=(-1)^n π/4 + πn x=(-1)^n π/12 + πn/3 Подбираем корни: n=0 n=1, х=π/4 n=-1 ∉ [0;2π] n=2 x=7π/12 n=3 x=11π/12 n=4 x=17π/12 n=5 x=19π/12 n=6 x= 25π/12∉[0;2π]
